|name capture||computing dictionary|
(\ x . \ y . x y) y --> \ y . y y (WRONG)
This problem arises because two distinct variables have the same name. The most common solution is to rename the bound variable using alpha conversion:
(\ x . \ y' . x y') y --> \ y' . y y'
Another solution is to use de Bruijn notation.
Note that the argument expression, y, contained a free variable. The whole expression above must therefore be notionally contained within the body of some lambda abstraction which binds y. If we never reduce inside the body of a lambda abstraction (as in reduction to weak head normal form) then name capture cannot occur.
(01 Mar 1995)
|Bookmark with:||word visualiser||Go and visit our forums|